(4x+3)^2+(3x-1)(4x+3)=0

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Solution for (4x+3)^2+(3x-1)(4x+3)=0 equation: 



(4x+3)^2+(3x-1)(4x+3)=0

We multiply parentheses ..

(+12x^2+9x-4x-3)+(4x+3)^2=0

We get rid of parentheses

12x^2+9x-4x+(4x+3)^2-3=0

We add all the numbers together, and all the variables

12x^2+5x+(4x+3)^2-3=0

We move all terms containing x to the left, all other terms to the right

12x^2+5x+(4x+3)^2=3

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